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Pulley with mass

Intermediate

Pulley inertia reduces the acceleration of attached masses.

Key relationa = (m₁−m₂)g/(m₁+m₂+I/R²)

A real pulley has moment of inertia I, so tensions on both sides differ: (T₁ − T₂)R = Iα with α = a/R. The acceleration becomes a = (m₁ − m₂)g/(m₁ + m₂ + I/R²).

Worked example

Heavy pulleys slow the system.

Common mistake

Don't assume equal tension.

In more detail

A pulley with mass, rotating as the rope moves, does not have equal tension on both sides. The difference in tensions provides the torque that gives the pulley its angular acceleration.

Real-world uses

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Frequently asked questions

Can I ignore the pulley's mass?

Only if it is very light compared with the other masses.

How do I include it?

Use τ = Iα for the pulley and combine with F = ma for the masses.

When is the pulley's mass ignored?

When it is light and the rope does not slip, so the tension is the same on both sides and the pulley's inertia can be neglected.

Related topics in Rotational Motion

Inertia tensor · Principal axes · Torque on a dipole · Atwood with real pulley · Yo-yo and unwinding cylinder · Angular impulse

← All Rotational Motion topics