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Moment of inertia of a rod

Intermediate

About the centre or the end of a uniform rod.

Key relationI = mL²/12; mL²/3

About its centre I = mL²/12; about an end I = mL²/3 (parallel axis theorem with d = L/2).

Worked example

1.2 kg, 1 m: 0.1 and 0.4 kg·m².

Common mistake

Use the right axis.

In more detail

For a thin uniform rod of mass M and length L rotating about its centre, I = ML²/12. About one end, I = ML²/3.

Real-world uses

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Frequently asked questions

Why is the end value bigger?

Because more mass is further from the axis, so the moment of inertia is larger.

Does the rod's thickness matter?

For a thin rod, no. For a thick one, the formula changes.

Why is the moment of inertia larger about the end?

More of the mass is further from that axis, and the formula uses the square of each distance from the axis.

Related topics in Rotational Motion

Centre of gravity · Stability and toppling · Moment of inertia · Moment of inertia of a ring · Moment of inertia of a disc · Moment of inertia of a solid sphere

← All Rotational Motion topics