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Kinetic interpretation of temperature

Intermediate

Temperature is proportional to mean translational kinetic energy.

Key relation⟨K⟩ = (3/2)k_BT

Comparing P = ⅓nm⟨v²⟩ with PV = NkT gives ⟨½mv²⟩ = (3/2)kT: temperature is proportional to the mean translational kinetic energy.

Worked example

At 300 K the average kinetic energy is 6.2×10⁻²¹ J (0.039 eV).

Common mistake

It applies to translational energy, independent of molecule mass.

In more detail

Temperature is proportional to the average translational kinetic energy of gas molecules, ⟨KE⟩ = (3/2)kT. Higher temperature means faster average motion.

Real-world uses

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Frequently asked questions

Is temperature the average speed?

No, it is proportional to the average kinetic energy, which depends on speed squared.

What is k?

The Boltzmann constant, linking temperature to energy.

Is temperature the same as the energy of one molecule?

No. Temperature relates to the average kinetic energy across many molecules, not the energy of any single one.

Related topics in Kinetic Theory & Statistical Physics

Brownian motion · Ideal gas assumptions · Pressure from molecular collisions · Boltzmann constant · RMS speed · Mean free path

← All Kinetic Theory & Statistical Physics topics