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Most probable speed

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Peak of the speed distribution.

Key relationv_p = √(2kT/m)

The peak of f(v) is v_p = √(2kT/m).

Worked example

N₂ at 300 K: 422 m/s.

Common mistake

Smaller than v_rms and the mean.

In more detail

The most probable speed is the speed at which the Maxwell-Boltzmann distribution peaks, v_p = sqrt(2kT/m). It is lower than the mean and rms speeds.

Real-world uses

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Frequently asked questions

Why are there three speeds?

Mean, rms and most probable speeds weight the distribution differently.

Which is largest?

The rms speed is largest, followed by the mean, then the most probable.

Is the most probable speed the average?

No. The most probable speed is the peak of the distribution, which is slightly lower than the average speed.

Related topics in Kinetic Theory & Statistical Physics

Equipartition theorem · Specific heats of gases · Maxwell–Boltzmann distribution · Average, rms and most probable speeds · Law of atmospheres · Diffusion

← All Kinetic Theory & Statistical Physics topics