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Variation of g with depth

Intermediate

Inside the Earth, g falls linearly toward the centre.

Key relationg' = g(1−d/R)

Inside a uniform Earth only the mass inside radius r attracts, so g' = g(1 − d/R), falling linearly to zero at the centre.

Worked example

At half the radius g' = 4.9 m/s².

Common mistake

Real Earth is denser at the core, so g first slightly increases.

In more detail

Inside a uniform Earth, g decreases linearly with depth, becoming zero at the centre. Only the mass below the point contributes to the pull there.

Real-world uses

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Frequently asked questions

Is g zero at the centre of the Earth?

Yes, in a uniform-density model, the mass pulling outward cancels the mass pulling inward.

Why does depth reduce g?

Because the mass outside the point at depth contributes nothing to the net pull.

Why does g fall inside the Earth?

Only the mass below you pulls on you, and that mass shrinks as you go deeper, so the net pull weakens.

Related topics in Gravitation & Orbits

Gravitational constant G · Acceleration due to gravity · Variation of g with altitude · Effect of Earth's rotation on g · Gravitational field · Gravitational potential energy

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