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Equilibrium of concurrent forces

Intermediate

Lami's theorem links three forces in equilibrium.

Key relationF₁/sinα = F₂/sinβ = F₃/sinγ

Three forces in equilibrium on a point form a closed triangle, so Lami's theorem applies: F₁/sinα = F₂/sinβ = F₃/sinγ, with each angle opposite its force.

Worked example

A 100 N weight hanging from two ropes at 45° each: each tension ≈ 70.7 N.

Common mistake

Lami's angles are between the other two forces, opposite the one in the numerator.

In more detail

Concurrent forces all act through the same point. An object is in equilibrium when the vector sum of these forces is zero, which can be checked by resolving forces into components.

Real-world uses

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Frequently asked questions

How do I check equilibrium with three forces?

Use a closed triangle of forces, or resolve each force into components and check both sums are zero.

Do forces need to be at right angles?

No. Components allow any angles to be handled.

When is Lami's theorem useful?

When three forces are in equilibrium and you know the angles between them, it gives the forces without resolving components.

Related topics in Newton's Laws & Forces

Spring force · Springs in series and parallel · Hooke's law limits · Torque and equilibrium · Center of mass · Motion of center of mass

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